# how to write Program to find the sum of each row & column of a matrix of size n x m andif matrix is square, find the sum of the diagonals also.

Hello friends, Welcome to your **Techgsr.co** blog. And today in this article we will learn about **how to write Program to find the sum of each row & column of a matrix of size n x m andif matrix is square, find the sum of the diagonals also.** .So let’s go to our topic

#include <iostream.h> #include <conio.h> int main() { clrscr(); int A[10][10],m,n,x,y,sum=0; //Create a Matrix A cout << “Enter number of rows and columns in Matrix A : \n”; cin>>n>>m; cout << “Enter elements of Matrix A : \n”; for(x=1;x<n+1;++x) for(y=1;y<m+1;++y) cin>>A[x][y]; //Find sum of each row for(x=1;x<n+1;++x) { A[x][m+1]=0; for(y=1;y<m+1;++y) A[x][m+1]=A[x][m+1]+A[x][y]; } //Find sum of each column for(y=1;y<m+1;++y) { A[n+1][y]=0; for(x=1;x<n+1;++x) A[n+1][y]+=A[x][y]; }cout << “\nMatrix A, Row Sum (Last Column)” << ” and Column Sum (Last Row) : \n”; for(x=1;x<n+1;++x) { for(y=1;y<m+2;++y) cout << A[x][y] << ” “; cout << “\n”; } //Print sum of each column x=n+1; for(y=1;y<m+1;++y) cout << A[x][y] << ” “; cout << “\n”; if(m==n) { for(x=1;x<m+1;x++) for(y=1;y<n+1;y++) if(x==y) sum+=A[x][y]; else if(y==m-(x+1)) sum+=A[x][y]; } cout << “Sum of diagonal elements is : ” << sum << endl; getch(); return 0; }

This program takes in the number of rows (n) and columns (m) as well as the elements as

a screen input in a matrix n x m.

It then calculates the sum of each row and each column and outputs it using the ‘cout’

command.

Also, if it is a square matrix, it calculates the sum of diagonal elements and prints it out.

**INPUT** :

3 3

9 8 7 6 5 4 3 2 1

**OUTPUT** :

Matrix A, Row Sum(Last Column) and Column Sum(Last Row) :

9 8 7 24

6 5 4 15

3 2 1 6

18

15

12

Sum of diagonal elements is : 15

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