how to write Program to find the sum of each row & column of a matrix of size n x m andif matrix is square, find the sum of the diagonals also.

Hello friends, Welcome to your Techgsr.co blog. And today in this article we will learn about how to write Program to find the sum of each row & column of a matrix of size n x m andif matrix is square, find the sum of the diagonals also. .So let’s go to our topic

#include <iostream.h>
#include <conio.h>
int main()
{
clrscr();
int A[10][10],m,n,x,y,sum=0;
//Create a Matrix A
cout << “Enter number of rows and columns in Matrix A : \n”;
cin>>n>>m;
cout << “Enter elements of Matrix A : \n”;
for(x=1;x<n+1;++x)
for(y=1;y<m+1;++y)
cin>>A[x][y];
//Find sum of each row
for(x=1;x<n+1;++x)
{
A[x][m+1]=0;
for(y=1;y<m+1;++y)
A[x][m+1]=A[x][m+1]+A[x][y];
}
//Find sum of each column
for(y=1;y<m+1;++y)
{
A[n+1][y]=0;
for(x=1;x<n+1;++x)
A[n+1][y]+=A[x][y];
}cout << “\nMatrix A, Row Sum (Last Column)” << ” and Column Sum (Last Row) : \n”;
for(x=1;x<n+1;++x)
{
for(y=1;y<m+2;++y)
cout << A[x][y] << ”
“;
cout << “\n”;
}
//Print sum of each column
x=n+1;
for(y=1;y<m+1;++y)
cout << A[x][y] << ”
“;
cout << “\n”;
if(m==n)
{
for(x=1;x<m+1;x++)
for(y=1;y<n+1;y++)
if(x==y)
sum+=A[x][y];
else
if(y==m-(x+1))
sum+=A[x][y];
}
cout << “Sum of diagonal elements is : ” << sum << endl;
getch();
return 0;
}

This program takes in the number of rows (n) and columns (m) as well as the elements as
a screen input in a matrix n x m.
It then calculates the sum of each row and each column and outputs it using the ‘cout’
command.
Also, if it is a square matrix, it calculates the sum of diagonal elements and prints it out.

INPUT :
3 3
9 8 7 6 5 4 3 2 1
OUTPUT :
Matrix A, Row Sum(Last Column) and Column Sum(Last Row) :
9 8 7 24
6 5 4 15
3 2 1 6
18
15
12
Sum of diagonal elements is : 15

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