how to create Program to convert 2-digit octal number into binary number and print it

Hello friends, Welcome to your Techgsr.co blog. And today in this article we will learn about how to create Program to convert 2-digit octal number into binary number and print it .So let’s go to our topic

#include <iostream.h>
#include <conio.h>
void octobin(int);
void main()
{
clrscr();
int a;
cout << “Enter a 2-digit octal number : “;
cin>>a;
octobin(a);
getch();
}
void octobin(int oct)
{
long bnum=0;
int A[6];
//Each octal digit is converted into 3 bits, 2 octal digits = 6 bits.
int a1,a2,quo,rem;
a2=oct/10;
a1=oct-a2*10;
for(int x=0;x<6;x++)
{
A[x]=0;
}
//Storing the remainders of the one’s octal digit in the array.
for (x=0;x<3;x++){
quo=a1/2;
rem=a1%2;
A[x]=rem;
a1=quo;
}
//Storing the remainders of the ten’s octal digit in the array.
for(x=3;x<6;x++)
{
quo=a2/2;
rem=a2%2;
A[x]=rem;
a2=quo;
}
//Obtaining the binary number from the remainders.
for(x=x-1;x>=0;x—)
{
bnum*=10;
bnum+=A[x];
}
cout << “The binary number for the octal number ” << oct << ” is ” << bnum << “.” <<
endl;
}

This program takes in a two-digit octal number a as a screen input from the user.
It then converts the octal number into a binary number and outputs it using the ‘cout’
command.
INPUT :
13
OUTPUT :The binary number for the octal number 13 is 1011.

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